(x^2-3x-10)(4x+7)=0

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Solution for (x^2-3x-10)(4x+7)=0 equation: 


Simplifying
(x2 + -3x + -10)(4x + 7) = 0

Reorder the terms:
(-10 + -3x + x2)(4x + 7) = 0

Reorder the terms:
(-10 + -3x + x2)(7 + 4x) = 0

Multiply (-10 + -3x + x2) * (7 + 4x)
(-10(7 + 4x) + -3x * (7 + 4x) + x2(7 + 4x)) = 0
((7 * -10 + 4x * -10) + -3x * (7 + 4x) + x2(7 + 4x)) = 0
((-70 + -40x) + -3x * (7 + 4x) + x2(7 + 4x)) = 0
(-70 + -40x + (7 * -3x + 4x * -3x) + x2(7 + 4x)) = 0
(-70 + -40x + (-21x + -12x2) + x2(7 + 4x)) = 0
(-70 + -40x + -21x + -12x2 + (7 * x2 + 4x * x2)) = 0
(-70 + -40x + -21x + -12x2 + (7x2 + 4x3)) = 0

Combine like terms: -40x + -21x = -61x
(-70 + -61x + -12x2 + 7x2 + 4x3) = 0

Combine like terms: -12x2 + 7x2 = -5x2
(-70 + -61x + -5x2 + 4x3) = 0

Solving
-70 + -61x + -5x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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